1 EXERCICE : VERIFICATION D’UN ARBRE 1. SECTION S1 : VERIFICATION EN STATIQUE τ

1 EXERCICE : VERIFICATION D’UN ARBRE 1. SECTION S1 : VERIFICATION EN STATIQUE τnominal = 170 MPa Kp = 0.871 Kq = 0.707 Kto = 1.21 τmaxi = 206 MPa σe = 356.4 MPa α α α αS = 1.71 < 2 P Pr ro op po os si it ti io on n 1 1 : : 3 38 8 N Ni iC Cr rM Mo o1 16 6 R Rp p0 0, ,2 2 = = 9 90 00 0 M MP Pa a P Pr ro op po os si it ti io on n 2 2 : : d di ia am mè èt tr re e i in nt té ér ri ie eu ur r = = 1 18 8 m mm m 2. SECTION S2 : VERIFICATION EN STATIQUE σfn = 9.23 MPa τοn = 72.4 MPa Kp = 5.20 Kq = 2.74 Ktf = 2.79 Kto = 2.18 σe maxi = 275 MPa α α α αS = 2.22 > 2 3. SECTION S2 : VERIFICATION EN FATIGUE tοn = 72.4 MPa σme = 125.4 MPa σfn = 9.23 MPa σae = 25.8 MPa KS = 0.96 cf = 5.06 co = 2.56 Rmp = 1217 MPa σDp = 442 MPa α α α αF = 8.05 > 2 2 4. SECTION S3 : VERIFICATION EN STATIQUE σtn = 4.3 MPa σfn = 48.9 MPa tοn = 35.9 MPa Kp = 6.14 Kq = 2.739 Ktt = 3.12 Ktf = 2.90 Kto = 2.32 σe = 212 MPa α α α αS = 2.88 > 2 5. SECTION S3 : VERIFICATION EN FATIGUE σme = 62.3 MPa σae = 141.8 MPa KS = 0.96 ct = 5.00 cf = 5.05 co = 2.55 cme = 2.57 Rmp = 1217 MPa σDp = 442 MPa α α α αF = 2.84 > 2 6. SECTION S4 : VERIFICATION EN STATIQUE Modèle a σtn = 6.5 MPa σfn = 79.3 MPa tοn = 54.6 MPa Kp = 8.67 Kq = 2.74 Ktt = 5.60 Ktf = 5.105 Kto = 3.07 σe = 528 MPa α α α αS = 1.15 < 2 Modèle b σtn = 6.5 MPa σfn = 79.3 MPa tοn = 54.6 MPa Kp = 8.67 Kq = 2.74 Ktt = 3. 21 Ktf = 3.07 Kto = 2.62 σe = 362 MPa α α α αS = 1.68 < 2 7. SECTION S4 : VERIFICATION EN FATIGUE σme = 94.7 MPa σae = 405 MPa KS = 0.96 ct = 10.00 cf = 10.06 co = 5.06 cme = 5.10 Rmp = 1277 MPa σDp = 455 MPa α α α αF = 1.07 < 2 σme = 94.7 MPa σae = 243.5 MPa KS = 0.96 ct = 10.00 cf = 10.05 co = 5.08 cme = 5.08 Rmp = 1278 MPa σDp = 455 MPa α α α αF = 1.72 < 2 uploads/s1/ exercice-arbres-corrige.pdf

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  • Publié le Oct 15, 2022
  • Catégorie Administration
  • Langue French
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